(7/5x)=35

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Solution for (7/5x)=35 equation: 



(7/5x)=35

We move all terms to the left:

(7/5x)-(35)=0



Domain of the equation: 5x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+7/5x)-35=0

We get rid of parentheses

7/5x-35=0

We multiply all the terms by the denominator


-35*5x+7=0

Wy multiply elements

-175x+7=0

We move all terms containing x to the left, all other terms to the right

-175x=-7

x=-7/-175

x=1/25

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