(7/4x+16)+2=(-8/x+4)

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Solution for (7/4x+16)+2=(-8/x+4) equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(7/4)*x+2+16 = 4-8/x // - 4-8/x

(7/4)*x-(-8/x)-4+2+16 = 0

(7/4)*x+8*x^-1-4+2+16 = 0

7/4*x^1+8*x^-1+14*x^0 = 0

(7/4*x^2+14*x^1+8*x^0)/(x^1) = 0 // * x^2

x^1*(7/4*x^2+14*x^1+8*x^0) = 0

x^1

(7/4)*x^2+14*x+8 = 0

(7/4)*x^2+14*x+8 = 0

DELTA = 14^2-(4*8*(7/4))

DELTA = 140

DELTA > 0

x = (140^(1/2)-14)/(2*(7/4)) or x = (-140^(1/2)-14)/(2*(7/4))

x = 2/7*(2*35^(1/2)-14) or x = 2/7*(-2*35^(1/2)-14)

x in { 2/7*(-2*35^(1/2)-14), 2/7*(2*35^(1/2)-14)}

x in { 2/7*(-2*35^(1/2)-14), 2/7*(2*35^(1/2)-14) }

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