(7/4)+(2x-3)/5=4-x

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Solution for (7/4)+(2x-3)/5=4-x equation: 


x in (-oo:+oo)

(2*x-3)/5+7/4 = 4-x // - 4-x

(2*x-3)/5+x+7/4-4 = 0

(4*(2*x-3))/(4*5)+(4*5*x)/(4*5)+(5*7)/(4*5)+(-4*4*5)/(4*5) = 0

4*(2*x-3)+4*5*x+5*7-4*4*5 = 0

28*x-80-12+35 = 0

28*x-80+23 = 0

28*x-57 = 0

(28*x-57)/(4*5) = 0

(28*x-57)/(4*5) = 0 // * 4*5

28*x-57 = 0

28*x-57 = 0 // + 57

28*x = 57 // : 28

x = 57/28

x = 57/28

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