(7/3x)-(11/2x)=-1

Solution for (7/3x)-(11/2x)=-1 equation:

(7/3x)-(11/2x)=-1

We move all terms to the left:

(7/3x)-(11/2x)-(-1)=0


Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R



Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+7/3x)-(+11/2x)-(-1)=0

We add all the numbers together, and all the variables

(+7/3x)-(+11/2x)+1=0

We get rid of parentheses

7/3x-11/2x+1=0

We calculate fractions


14x/6x^2+(-33x)/6x^2+1=0

We multiply all the terms by the denominator


14x+(-33x)+1*6x^2=0

Wy multiply elements

6x^2+14x+(-33x)=0

We get rid of parentheses

6x^2+14x-33x=0

We add all the numbers together, and all the variables

6x^2-19x=0

a = 6; b = -19; c = 0;
Δ = b2-4ac
Δ = -192-4·6·0
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-19}{2*6}=\frac{0}{12}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+19}{2*6}=\frac{38}{12}
=3+1/6
$