(7/2x)-(5/x)=5

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Solution for (7/2x)-(5/x)=5 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(7/2)*x-(5/x) = 5 // - 5

(7/2)*x-(5/x)-5 = 0

(7/2)*x-5*x^-1-5 = 0

7/2*x^1-5*x^-1-5*x^0 = 0

(7/2*x^2-5*x^1-5*x^0)/(x^1) = 0 // * x^2

x^1*(7/2*x^2-5*x^1-5*x^0) = 0

x^1

(7/2)*x^2-5*x-5 = 0

(7/2)*x^2-5*x-5 = 0

DELTA = (-5)^2-(-5*4*(7/2))

DELTA = 95

DELTA > 0

x = (95^(1/2)+5)/(2*(7/2)) or x = (5-95^(1/2))/(2*(7/2))

x = (95^(1/2)+5)/7 or x = (5-95^(1/2))/7

x in { (5-95^(1/2))/7, (95^(1/2)+5)/7}

x in { (5-95^(1/2))/7, (95^(1/2)+5)/7 }

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