(7/2)p-(p+4)=6

Solution for (7/2)p-(p+4)=6 equation:

(7/2)p-(p+4)=6

We move all terms to the left:

(7/2)p-(p+4)-(6)=0


Domain of the equation: 2)p!=0

p!=0/1

p!=0

p∈R


We add all the numbers together, and all the variables

(+7/2)p-(p+4)-6=0

We multiply parentheses

7p^2-(p+4)-6=0

We get rid of parentheses

7p^2-p-4-6=0

We add all the numbers together, and all the variables

7p^2-1p-10=0

a = 7; b = -1; c = -10;
Δ = b2-4ac
Δ = -12-4·7·(-10)
Δ = 281
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{281}}{2*7}=\frac{1-\sqrt{281}}{14}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{281}}{2*7}=\frac{1+\sqrt{281}}{14}
$