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(7/12)x=105
We move all terms to the left:
(7/12)x-(105)=0
Domain of the equation: 12)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+7/12)x-105=0
We multiply parentheses
7x^2-105=0
a = 7; b = 0; c = -105;
Δ = b2-4ac
Δ = 02-4·7·(-105)
Δ = 2940
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2940}=\sqrt{196*15}=\sqrt{196}*\sqrt{15}=14\sqrt{15}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14\sqrt{15}}{2*7}=\frac{0-14\sqrt{15}}{14} =-\frac{14\sqrt{15}}{14} =-\sqrt{15} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14\sqrt{15}}{2*7}=\frac{0+14\sqrt{15}}{14} =\frac{14\sqrt{15}}{14} =\sqrt{15} $
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