(7/10c)-8-1/2c=-16

Solution for (7/10c)-8-1/2c=-16 equation:

(7/10c)-8-1/2c=-16

We move all terms to the left:

(7/10c)-8-1/2c-(-16)=0


Domain of the equation: 10c)!=0

c!=0/1

c!=0

c∈R



Domain of the equation: 2c!=0

c!=0/2

c!=0

c∈R


We add all the numbers together, and all the variables

(+7/10c)-1/2c-8-(-16)=0

We add all the numbers together, and all the variables

(+7/10c)-1/2c+8=0

We get rid of parentheses

7/10c-1/2c+8=0

We calculate fractions


14c/20c^2+(-10c)/20c^2+8=0

We multiply all the terms by the denominator


14c+(-10c)+8*20c^2=0

Wy multiply elements

160c^2+14c+(-10c)=0

We get rid of parentheses

160c^2+14c-10c=0

We add all the numbers together, and all the variables

160c^2+4c=0

a = 160; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·160·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*160}=\frac{-8}{320}
=-1/40
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*160}=\frac{0}{320}
=0
$