(7/10)x=6-3x

Solution for (7/10)x=6-3x equation:

(7/10)x=6-3x

We move all terms to the left:

(7/10)x-(6-3x)=0


Domain of the equation: 10)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+7/10)x-(-3x+6)=0

We multiply parentheses

7x^2-(-3x+6)=0

We get rid of parentheses

7x^2+3x-6=0

a = 7; b = 3; c = -6;
Δ = b2-4ac
Δ = 32-4·7·(-6)
Δ = 177
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{177}}{2*7}=\frac{-3-\sqrt{177}}{14}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{177}}{2*7}=\frac{-3+\sqrt{177}}{14}
$