(7/(3z-2))=(5/(4z))

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Solution for (7/(3z-2))=(5/(4z)) equation: 


D( z )

4*z = 0

3*z-2 = 0

4*z = 0

4*z = 0

4*z = 0 // : 4

z = 0

3*z-2 = 0

3*z-2 = 0

3*z-2 = 0 // + 2

3*z = 2 // : 3

z = 2/3

z in (-oo:0) U (0:2/3) U (2/3:+oo)

7/(3*z-2) = 5/(4*z) // - 5/(4*z)

7/(3*z-2)-(5/(4*z)) = 0

7/(3*z-2)+(-5/4)*z^-1 = 0

7/(3*z-2)-5/(4*z) = 0

(4*7*z)/(4*z*(3*z-2))+(-5*(3*z-2))/(4*z*(3*z-2)) = 0

4*7*z-5*(3*z-2) = 0

13*z+10 = 0

(13*z+10)/(4*z*(3*z-2)) = 0

(13*z+10)/(4*z*(3*z-2)) = 0 // * 4*z*(3*z-2)

13*z+10 = 0

13*z+10 = 0 // - 10

13*z = -10 // : 13

z = -10/13

z = -10/13

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