(7-4x)/3=(1-3x)/2

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Solution for (7-4x)/3=(1-3x)/2 equation: 


x in (-oo:+oo)

(7-(4*x))/3 = (1-(3*x))/2 // - (1-(3*x))/2

(7-(4*x))/3-((1-(3*x))/2) = 0

(7-4*x)/3-((1-3*x)/2) = 0

(7-4*x)/3+(-1*(1-3*x))/2 = 0

(2*(7-4*x))/(2*3)+(-1*3*(1-3*x))/(2*3) = 0

2*(7-4*x)-1*3*(1-3*x) = 0

x+11 = 0

(x+11)/(2*3) = 0

(x+11)/(2*3) = 0 // * 2*3

x+11 = 0

x+11 = 0 // - 11

x = -11

x = -11

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