(7-3x)/(2)=(4x-15)/(3)

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Solution for (7-3x)/(2)=(4x-15)/(3) equation: 



(7-3x)/(2)=(4x-15)/(3)

We move all terms to the left:

(7-3x)/(2)-((4x-15)/(3))=0

We add all the numbers together, and all the variables

(-3x+7)/2-((4x-15)/3)=0

We calculate fractions


(-3x)/()+(-((4x-15)*2)/()=0



We calculate terms in parentheses: +(-((4x-15)*2)/(), so:

-((4x-15)*2)/(

We multiply all the terms by the denominator


-((4x-15)*2)



We calculate terms in parentheses: -((4x-15)*2), so:

(4x-15)*2

We multiply parentheses

8x-30

Back to the equation:

-(8x-30)



We get rid of parentheses

-8x+30

Back to the equation:

+(-8x+30)



We get rid of parentheses

(-3x)/()-8x+30=0

We multiply all the terms by the denominator


(-3x)-8x*()+30*()=0

We add all the numbers together, and all the variables

(-3x)-8x*()=0

We get rid of parentheses

-3x-8x*()=0

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