(7-2x)6=(12x+18)1/3

Solution for (7-2x)6=(12x+18)1/3 equation:

(7-2x)6=(12x+18)1/3

We move all terms to the left:

(7-2x)6-((12x+18)1/3)=0

We add all the numbers together, and all the variables

(-2x+7)6-((12x+18)1/3)=0

We multiply parentheses

-12x-((12x+18)1/3)+42=0

We multiply all the terms by the denominator


-12x*3)-((12x+18)1+42*3)=0

We add all the numbers together, and all the variables

-12x*3)-((12x+18)1=0

Wy multiply elements

-36x^2=0

a = -36; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-36)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-72}=0$