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(7-2x)*2x=12
We move all terms to the left:
(7-2x)*2x-(12)=0
We add all the numbers together, and all the variables
(-2x+7)*2x-12=0
We multiply parentheses
-4x^2+14x-12=0
a = -4; b = 14; c = -12;
Δ = b2-4ac
Δ = 142-4·(-4)·(-12)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2}{2*-4}=\frac{-16}{-8} =+2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2}{2*-4}=\frac{-12}{-8} =1+1/2 $
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