(7-2x^2)/(9-2x)*5

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Solution for (7-2x^2)/(9-2x)*5 equation: 


D( x )

9-(2*x) = 0

9-(2*x) = 0

9-(2*x) = 0

9-2*x = 0

9-2*x = 0 // - 9

-2*x = -9 // : -2

x = -9/(-2)

x = 9/2

x in (-oo:9/2) U (9/2:+oo)

5*((7-(2*x^2))/(9-(2*x))) = 0

5*((7-2*x^2)/(9-2*x)) = 0

(5*(7-2*x^2))/(9-2*x) = 0

( 5 )

5 = 0

x belongs to the empty set

( 7-2*x^2 )

-2*x^2 = -7 // : -2

x^2 = 7/2

x^2 = 7/2 // ^ 1/2

abs(x) = (7/2)^(1/2)

x = (7/2)^(1/2) or x = -(7/2)^(1/2)

x in { (7/2)^(1/2), -(7/2)^(1/2) }

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