(7-2i)(7+2i)=0

Solution for (7-2i)(7+2i)=0 equation:

(7-2i)(7+2i)=0

We add all the numbers together, and all the variables

(-2i+7)(2i+7)=0

We multiply parentheses ..

(-4i^2-14i+14i+49)=0

We get rid of parentheses

-4i^2-14i+14i+49=0

We add all the numbers together, and all the variables

-4i^2+49=0

a = -4; b = 0; c = +49;
Δ = b2-4ac
Δ = 02-4·(-4)·49
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-28}{2*-4}=\frac{-28}{-8}
=3+1/2
$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+28}{2*-4}=\frac{28}{-8}
=-3+1/2
$