(7+x)*(x-49)=(9+x)*(x-81)

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Solution for (7+x)*(x-49)=(9+x)*(x-81) equation: 



(7+x)(x-49)=(9+x)(x-81)

We move all terms to the left:

(7+x)(x-49)-((9+x)(x-81))=0

We add all the numbers together, and all the variables

(x+7)(x-49)-((x+9)(x-81))=0

We multiply parentheses ..

(+x^2-49x+7x-343)-((x+9)(x-81))=0



We calculate terms in parentheses: -((x+9)(x-81)), so:

(x+9)(x-81)

We multiply parentheses ..

(+x^2-81x+9x-729)

We get rid of parentheses

x^2-81x+9x-729

We add all the numbers together, and all the variables

x^2-72x-729

Back to the equation:

-(x^2-72x-729)



We get rid of parentheses

x^2-x^2-49x+7x+72x-343+729=0

We add all the numbers together, and all the variables

30x+386=0

We move all terms containing x to the left, all other terms to the right

30x=-386

x=-386/30

x=-12+13/15

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