(7+x)(7-x)=0

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Solution for (7+x)(7-x)=0 equation:



(7+x)(7-x)=0
We add all the numbers together, and all the variables
(x+7)(-1x+7)=0
We multiply parentheses ..
(-1x^2+7x-7x+49)=0
We get rid of parentheses
-1x^2+7x-7x+49=0
We add all the numbers together, and all the variables
-1x^2+49=0
a = -1; b = 0; c = +49;
Δ = b2-4ac
Δ = 02-4·(-1)·49
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14}{2*-1}=\frac{-14}{-2} =+7 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14}{2*-1}=\frac{14}{-2} =-7 $

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