(7+3/8+4)x=-6

Solution for (7+3/8+4)x=-6 equation:

(7+3/8+4)x=-6

We move all terms to the left:

(7+3/8+4)x-(-6)=0


Domain of the equation: 8+4)x!=0

We move all terms containing x to the left, all other terms to the right

4)x!=-8

x!=-8/1

x!=-8

x∈R


We add all the numbers together, and all the variables

(3/8+11)x-(-6)=0

We add all the numbers together, and all the variables

(3/8+11)x+6=0

We multiply parentheses

3x^2+11x+6=0

a = 3; b = 11; c = +6;
Δ = b2-4ac
Δ = 112-4·3·6
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-7}{2*3}=\frac{-18}{6}
=-3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+7}{2*3}=\frac{-4}{6}
=-2/3
$