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(7+3)/3=2x-5
We move all terms to the left:
(7+3)/3-(2x-5)=0
We add all the numbers together, and all the variables
-(2x-5)+10/3=0
We get rid of parentheses
-2x+5+10/3=0
We multiply all the terms by the denominator
-2x*3+10+5*3=0
We add all the numbers together, and all the variables
-2x*3+25=0
Wy multiply elements
-6x+25=0
We move all terms containing x to the left, all other terms to the right
-6x=-25
x=-25/-6
x=4+1/6
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