(7)/(k-2)=(5/8)

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Solution for (7)/(k-2)=(5/8) equation: 


D( k )

k-2 = 0

k-2 = 0

k-2 = 0

k-2 = 0 // + 2

k = 2

k in (-oo:2) U (2:+oo)

7/(k-2) = 5/8 // - 5/8

7/(k-2)-(5/8) = 0

7/(k-2)-5/8 = 0

(7*8)/(8*(k-2))+(-5*(k-2))/(8*(k-2)) = 0

7*8-5*(k-2) = 0

66-5*k = 0

(66-5*k)/(8*(k-2)) = 0

(66-5*k)/(8*(k-2)) = 0 // * 8*(k-2)

66-5*k = 0

66-5*k = 0 // - 66

-5*k = -66 // : -5

k = -66/(-5)

k = 66/5

k = 66/5

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