(7(1+3x))/2+1=3(-3+2x)

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Solution for (7(1+3x))/2+1=3(-3+2x) equation: 



(7(1+3x))/2+1=3(-3+2x)

We move all terms to the left:

(7(1+3x))/2+1-(3(-3+2x))=0

We add all the numbers together, and all the variables

(7(3x+1))/2-(3(2x-3))+1=0

We multiply all the terms by the denominator


(7(3x+1))-((3(2x-3)))*2+1*2=0



We calculate terms in parentheses: +(7(3x+1)), so:

7(3x+1)

We multiply parentheses

21x+7

Back to the equation:

+(21x+7)



We add all the numbers together, and all the variables

(21x+7)-((3(2x-3)))*2+2=0

We get rid of parentheses

21x-((3(2x-3)))*2+7+2=0

We add all the numbers together, and all the variables

21x-((3(2x-3)))*2+9=0

We move all terms containing x to the left, all other terms to the right

21x-((3(2x-3)))*2=-9

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