(6z/7)-(4z/9)=1

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Solution for (6z/7)-(4z/9)=1 equation: 


z in (-oo:+oo)

(6*z)/7-((4*z)/9) = 1 // - 1

(6*z)/7-((4*z)/9)-1 = 0

(6*z)/7+(-4/9)*z-1 = 0

26/63*z-1 = 0 // + 1

26/63*z = 1 // : 26/63

z = 1/26/63

z = 63/26

z = 63/26

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