(6y-3)=(4y+24)

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Solution for (6y-3)=(4y+24) equation: 



(6y-3)=(4y+24)

We move all terms to the left:

(6y-3)-((4y+24))=0

We get rid of parentheses

6y-((4y+24))-3=0



We calculate terms in parentheses: -((4y+24)), so:

(4y+24)

We get rid of parentheses

4y+24

Back to the equation:

-(4y+24)



We get rid of parentheses

6y-4y-24-3=0

We add all the numbers together, and all the variables

2y-27=0

We move all terms containing y to the left, all other terms to the right

2y=27

y=27/2

y=13+1/2

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