(6y-2)=(3y+20)

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Solution for (6y-2)=(3y+20) equation: 



(6y-2)=(3y+20)

We move all terms to the left:

(6y-2)-((3y+20))=0

We get rid of parentheses

6y-((3y+20))-2=0



We calculate terms in parentheses: -((3y+20)), so:

(3y+20)

We get rid of parentheses

3y+20

Back to the equation:

-(3y+20)



We get rid of parentheses

6y-3y-20-2=0

We add all the numbers together, and all the variables

3y-22=0

We move all terms containing y to the left, all other terms to the right

3y=22

y=22/3

y=7+1/3

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