(6y-10)+(3y-9)+(4y-9)=180

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Solution for (6y-10)+(3y-9)+(4y-9)=180 equation: 



(6y-10)+(3y-9)+(4y-9)=180

We move all terms to the left:

(6y-10)+(3y-9)+(4y-9)-(180)=0

We get rid of parentheses

6y+3y+4y-10-9-9-180=0

We add all the numbers together, and all the variables

13y-208=0

We move all terms containing y to the left, all other terms to the right

13y=208

y=208/13

y=16

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