(6y+3)+(4y-3)=90

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Solution for (6y+3)+(4y-3)=90 equation: 



(6y+3)+(4y-3)=90

We move all terms to the left:

(6y+3)+(4y-3)-(90)=0

We get rid of parentheses

6y+4y+3-3-90=0

We add all the numbers together, and all the variables

10y-90=0

We move all terms containing y to the left, all other terms to the right

10y=90

y=90/10

y=9

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