(6x3-3x2+5x)/(3x)

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Solution for (6x3-3x2+5x)/(3x) equation: 


D( x )

3*x = 0

3*x = 0

3*x = 0

3*x = 0 // : 3

x = 0

x in (-oo:0) U (0:+oo)

(6*x^3-(3*x^2)+5*x)/(3*x) = 0

(6*x^3-3*x^2+5*x)/(3*x) = 0

6*x^3-3*x^2+5*x = 0

x*(6*x^2-3*x+5) = 0

6*x^2-3*x+5 = 0

DELTA = (-3)^2-(4*5*6)

DELTA = -111

DELTA < 0

x = 0

x/(3*x) = 0

x = 0

x in { 0} 

x belongs to the empty set

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