(6x2+-15)=(5x2+-2x)

Solution for (6x2+-15)=(5x2+-2x) equation:

(6x^2+-15)=(5x^2+-2x)

We move all terms to the left:

(6x^2+-15)-((5x^2+-2x))=0

We use the square of the difference formula

(6x^2-15)-((5x^2-2x))=0

We get rid of parentheses

6x^2-((5x^2-2x))-15=0


We calculate terms in parentheses: -((5x^2-2x)), so:

(5x^2-2x)

We get rid of parentheses

5x^2-2x

Back to the equation:

-(5x^2-2x)


We get rid of parentheses

6x^2-5x^2+2x-15=0

We add all the numbers together, and all the variables

x^2+2x-15=0

a = 1; b = 2; c = -15;
Δ = b2-4ac
Δ = 22-4·1·(-15)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-8}{2*1}=\frac{-10}{2}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+8}{2*1}=\frac{6}{2}
=3
$