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(6x-8)(4x+2)=0
We multiply parentheses ..
(+24x^2+12x-32x-16)=0
We get rid of parentheses
24x^2+12x-32x-16=0
We add all the numbers together, and all the variables
24x^2-20x-16=0
a = 24; b = -20; c = -16;
Δ = b2-4ac
Δ = -202-4·24·(-16)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-44}{2*24}=\frac{-24}{48} =-1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+44}{2*24}=\frac{64}{48} =1+1/3 $
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