(6x-8)(2x+2)=0

Solution for (6x-8)(2x+2)=0 equation:

(6x-8)(2x+2)=0

We multiply parentheses ..

(+12x^2+12x-16x-16)=0

We get rid of parentheses

12x^2+12x-16x-16=0

We add all the numbers together, and all the variables

12x^2-4x-16=0

a = 12; b = -4; c = -16;
Δ = b2-4ac
Δ = -42-4·12·(-16)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-28}{2*12}=\frac{-24}{24}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+28}{2*12}=\frac{32}{24}
=1+1/3
$