(6x-6)+38)/2=7x-4

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Solution for (6x-6)+38)/2=7x-4 equation: 



(6x-6)+38)/2=7x-4

We move all terms to the left:

(6x-6)+38)/2-(7x-4)=0



Domain of the equation: 2-(7x!=0

We move all terms containing x to the left, all other terms to the right

-(7x!=-2

x∈R



We add all the numbers together, and all the variables

(6x-6)+38)/2-(7x=0

We get rid of parentheses

6x+38)/2-(7x-6=0

We multiply all the terms by the denominator


6x*2-(7x+38)-(7x-6*2=0

Wy multiply elements

12x-(7x+38)-(7x-6*2=0

We get rid of parentheses

12x-7x-(7x-6*2-38=0

We add all the numbers together, and all the variables

5x-(7x-6*2-38=0

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