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(6x-6)(7x+6)=0
We multiply parentheses ..
(+42x^2+36x-42x-36)=0
We get rid of parentheses
42x^2+36x-42x-36=0
We add all the numbers together, and all the variables
42x^2-6x-36=0
a = 42; b = -6; c = -36;
Δ = b2-4ac
Δ = -62-4·42·(-36)
Δ = 6084
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6084}=78$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-78}{2*42}=\frac{-72}{84} =-6/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+78}{2*42}=\frac{84}{84} =1 $
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