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(6x-5)=(x+50)
We move all terms to the left:
(6x-5)-((x+50))=0
We get rid of parentheses
6x-((x+50))-5=0
We calculate terms in parentheses: -((x+50)), so:We get rid of parentheses
(x+50)
We get rid of parentheses
x+50
Back to the equation:
-(x+50)
6x-x-50-5=0
We add all the numbers together, and all the variables
5x-55=0
We move all terms containing x to the left, all other terms to the right
5x=55
x=55/5
x=11
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