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(6x-5)(6x-5)=5x
We move all terms to the left:
(6x-5)(6x-5)-(5x)=0
We add all the numbers together, and all the variables
-5x+(6x-5)(6x-5)=0
We multiply parentheses ..
(+36x^2-30x-30x+25)-5x=0
We get rid of parentheses
36x^2-30x-30x-5x+25=0
We add all the numbers together, and all the variables
36x^2-65x+25=0
a = 36; b = -65; c = +25;
Δ = b2-4ac
Δ = -652-4·36·25
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-65)-25}{2*36}=\frac{40}{72} =5/9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-65)+25}{2*36}=\frac{90}{72} =1+1/4 $
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