(6x-40)+(x+20)=(180-3x)

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Solution for (6x-40)+(x+20)=(180-3x) equation: 



(6x-40)+(x+20)=(180-3x)

We move all terms to the left:

(6x-40)+(x+20)-((180-3x))=0

We add all the numbers together, and all the variables

(6x-40)+(x+20)-((-3x+180))=0

We get rid of parentheses

6x+x-((-3x+180))-40+20=0



We calculate terms in parentheses: -((-3x+180)), so:

(-3x+180)

We get rid of parentheses

-3x+180

Back to the equation:

-(-3x+180)



We add all the numbers together, and all the variables

7x-(-3x+180)-20=0

We get rid of parentheses

7x+3x-180-20=0

We add all the numbers together, and all the variables

10x-200=0

We move all terms containing x to the left, all other terms to the right

10x=200

x=200/10

x=20

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