(6x-4)+(7x-10)+47=180

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Solution for (6x-4)+(7x-10)+47=180 equation: 



(6x-4)+(7x-10)+47=180

We move all terms to the left:

(6x-4)+(7x-10)+47-(180)=0

We add all the numbers together, and all the variables

(6x-4)+(7x-10)-133=0

We get rid of parentheses

6x+7x-4-10-133=0

We add all the numbers together, and all the variables

13x-147=0

We move all terms containing x to the left, all other terms to the right

13x=147

x=147/13

x=11+4/13

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