(6x-35)+(4x-20)+19=180

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Solution for (6x-35)+(4x-20)+19=180 equation: 



(6x-35)+(4x-20)+19=180

We move all terms to the left:

(6x-35)+(4x-20)+19-(180)=0

We add all the numbers together, and all the variables

(6x-35)+(4x-20)-161=0

We get rid of parentheses

6x+4x-35-20-161=0

We add all the numbers together, and all the variables

10x-216=0

We move all terms containing x to the left, all other terms to the right

10x=216

x=216/10

x=21+3/5

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