(6x-30)=(40-x)

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Solution for (6x-30)=(40-x) equation: 



(6x-30)=(40-x)

We move all terms to the left:

(6x-30)-((40-x))=0

We add all the numbers together, and all the variables

(6x-30)-((-1x+40))=0

We get rid of parentheses

6x-((-1x+40))-30=0



We calculate terms in parentheses: -((-1x+40)), so:

(-1x+40)

We get rid of parentheses

-1x+40

Back to the equation:

-(-1x+40)



We get rid of parentheses

6x+1x-40-30=0

We add all the numbers together, and all the variables

7x-70=0

We move all terms containing x to the left, all other terms to the right

7x=70

x=70/7

x=10

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