(6x-3)=(3x+12)

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Solution for (6x-3)=(3x+12) equation: 



(6x-3)=(3x+12)

We move all terms to the left:

(6x-3)-((3x+12))=0

We get rid of parentheses

6x-((3x+12))-3=0



We calculate terms in parentheses: -((3x+12)), so:

(3x+12)

We get rid of parentheses

3x+12

Back to the equation:

-(3x+12)



We get rid of parentheses

6x-3x-12-3=0

We add all the numbers together, and all the variables

3x-15=0

We move all terms containing x to the left, all other terms to the right

3x=15

x=15/3

x=5

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