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(6x-3)(4x=12)=0
We move all terms to the left:
(6x-3)(4x-(12))=0
We multiply parentheses ..
(+24x^2-72x-12x+36)=0
We get rid of parentheses
24x^2-72x-12x+36=0
We add all the numbers together, and all the variables
24x^2-84x+36=0
a = 24; b = -84; c = +36;
Δ = b2-4ac
Δ = -842-4·24·36
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-84)-60}{2*24}=\frac{24}{48} =1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-84)+60}{2*24}=\frac{144}{48} =3 $
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