(6x-3)(10x+5)=0

Solution for (6x-3)(10x+5)=0 equation:

(6x-3)(10x+5)=0

We multiply parentheses ..

(+60x^2+30x-30x-15)=0

We get rid of parentheses

60x^2+30x-30x-15=0

We add all the numbers together, and all the variables

60x^2-15=0

a = 60; b = 0; c = -15;
Δ = b2-4ac
Δ = 02-4·60·(-15)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60}{2*60}=\frac{-60}{120}
=-1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60}{2*60}=\frac{60}{120}
=1/2
$