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(6x-23)=(3x+10)
We move all terms to the left:
(6x-23)-((3x+10))=0
We get rid of parentheses
6x-((3x+10))-23=0
We calculate terms in parentheses: -((3x+10)), so:We get rid of parentheses
(3x+10)
We get rid of parentheses
3x+10
Back to the equation:
-(3x+10)
6x-3x-10-23=0
We add all the numbers together, and all the variables
3x-33=0
We move all terms containing x to the left, all other terms to the right
3x=33
x=33/3
x=11
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