(6x-2+(-2x+3))/2=x+6

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Solution for (6x-2+(-2x+3))/2=x+6 equation: 



(6x-2+(-2x+3))/2=x+6

We move all terms to the left:

(6x-2+(-2x+3))/2-(x+6)=0

We get rid of parentheses

(6x-2+(-2x+3))/2-x-6=0

We multiply all the terms by the denominator


(6x-2+(-2x+3))-x*2-6*2=0



We calculate terms in parentheses: +(6x-2+(-2x+3)), so:

6x-2+(-2x+3)

determiningTheFunctionDomain
6x+(-2x+3)-2

We get rid of parentheses

6x-2x+3-2

We add all the numbers together, and all the variables

4x+1

Back to the equation:

+(4x+1)



We add all the numbers together, and all the variables

(4x+1)-x*2-12=0

Wy multiply elements

(4x+1)-2x-12=0

We get rid of parentheses

4x-2x+1-12=0

We add all the numbers together, and all the variables

2x-11=0

We move all terms containing x to the left, all other terms to the right

2x=11

x=11/2

x=5+1/2

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