(6x-2)(4x+8)=0

Solution for (6x-2)(4x+8)=0 equation:

(6x-2)(4x+8)=0

We multiply parentheses ..

(+24x^2+48x-8x-16)=0

We get rid of parentheses

24x^2+48x-8x-16=0

We add all the numbers together, and all the variables

24x^2+40x-16=0

a = 24; b = 40; c = -16;
Δ = b2-4ac
Δ = 402-4·24·(-16)
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-56}{2*24}=\frac{-96}{48}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+56}{2*24}=\frac{16}{48}
=1/3
$