(6x-18)+2x=(8x+4)-22

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Solution for (6x-18)+2x=(8x+4)-22 equation: 



(6x-18)+2x=(8x+4)-22

We move all terms to the left:

(6x-18)+2x-((8x+4)-22)=0

We add all the numbers together, and all the variables

2x+(6x-18)-((8x+4)-22)=0

We get rid of parentheses

2x+6x-((8x+4)-22)-18=0



We calculate terms in parentheses: -((8x+4)-22), so:

(8x+4)-22

We get rid of parentheses

8x+4-22

We add all the numbers together, and all the variables

8x-18

Back to the equation:

-(8x-18)



We add all the numbers together, and all the variables

8x-(8x-18)-18=0

We get rid of parentheses

8x-8x+18-18=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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