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(6x-12)/(5x+15)=0
Domain of the equation: (5x+15)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
5x!=-15
x!=-15/5
x!=-3
x∈R
(6x-12)=0
We get rid of parentheses
6x-12=0
We move all terms containing x to the left, all other terms to the right
6x=12
x=12/6
x=2
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