(6x-11)+(4x-25)=133

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Solution for (6x-11)+(4x-25)=133 equation: 



(6x-11)+(4x-25)=133

We move all terms to the left:

(6x-11)+(4x-25)-(133)=0

We get rid of parentheses

6x+4x-11-25-133=0

We add all the numbers together, and all the variables

10x-169=0

We move all terms containing x to the left, all other terms to the right

10x=169

x=169/10

x=16+9/10

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