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(6x-10)(x)=24
We move all terms to the left:
(6x-10)(x)-(24)=0
We multiply parentheses
6x^2-10x-24=0
a = 6; b = -10; c = -24;
Δ = b2-4ac
Δ = -102-4·6·(-24)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-26}{2*6}=\frac{-16}{12} =-1+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+26}{2*6}=\frac{36}{12} =3 $
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