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(6x-1)(5x-1)=8
We move all terms to the left:
(6x-1)(5x-1)-(8)=0
We multiply parentheses ..
(+30x^2-6x-5x+1)-8=0
We get rid of parentheses
30x^2-6x-5x+1-8=0
We add all the numbers together, and all the variables
30x^2-11x-7=0
a = 30; b = -11; c = -7;
Δ = b2-4ac
Δ = -112-4·30·(-7)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{961}=31$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-31}{2*30}=\frac{-20}{60} =-1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+31}{2*30}=\frac{42}{60} =7/10 $
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